设函数f(x)=sin(πx/4-π/6)-2cos^2πx/8+1.若函数y=g（x）与y=f（x）图像关于直线x=1对称,求x属于[ 0,4/3 ] 时,y=g（x）的最大值?函数我算的是f（x）=根号3 *sin（πx/4 - π/3）,

设函数 f(x)=sin(2x+y),(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f x=SIN(2X+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+ φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+ φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(πx/2+π/4)x 设函数f(x)=sin(wx+t)(-π/2 设函数f(x)=sin(wx+t)(-π/2 设函数f(x)=sinπ/6（x),则f(1)+f(2)+f(3)+…f(2008)=? 设函数f(x)=sinπ/6（x),则f(1)+f(2)+f(3)+…f(2008)=? 设函数f(x)=sin(πx/4-π/6)-2cos²πx/8+1