①若(x+a)(x²-2x-1)中不含x²项,则a=( )A.2 B.-2 C.0 D.1②如果(x²+ax+8)(x²-3x+b)展开后不含常数项和x³项,求a,b的值.③请你说明对任意正整数n,式子n(n+5)-(n+2)(n-3)的值必定能被6整除.④
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①.X²-2X+1/X²-1 ÷ X²-X/X+1②.a-1/a²-4a+4 ÷ a²-1/a²-4③.x³-x²/x²-x ÷ x²-2x/x-1④.(x-y)²/x+y ÷ 1/y+x X 1/x-y帮下忙嘛 咯
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