∫2x^4+2x^2+1/x^2+1dx的不定积分!

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∫（x^2+1/x^4)dx ∫1/(x^4-x^2)dx 1/(x+x^2)dx ∫1+2x/x(1+x)*dx∫1+2x/x(1+x) * dx ∫(x^3-x^2+x+1)/(x^2+1) dx∫(x+4)/(x^2-x-2) dx ∫(x+2)/(4x-x^2)^1/2dx ∫(3x^4+x^2)/(x^2+1)dx ∫（(x+2)/4x(x^2-1)）dx 积分∫x/[(x^2+1)(x^2+4)]dx ∫x/(3+4x+x^2)^1/2dx ∫dx/x^2(1-x^2) ∫dx/x^2(1+x^2) ∫X^2/1-x^2 dx. ∫X^2/1-x^2 dx. ∫1/x^2+x+1dx ∫1/(x^2+x+1)dx ∫ (x+arctanx)/(1+x^2) dx ∫2 -1|x²-x|dx