3x+9=10 求x
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/17 16:41:34
x)3ж54Px&HU@
[C}c';z7ؿuz6yv .h
已知x=2π+1求 |x-1|+|x-2|+|x-3|+|x-4|+|x-5|+|x-6|+|x-7|+|x-8|+|x-9|+|x-10|
已知x=2π+1.求(X-1)+(X-2)+(X-3)+(X-4)+(X-5)+(X-6)+(X-7)+(X-8)+(X-9)+(X-10)
9+3x=10求x
3x+9=10 求x
10-x=9+3x 求X
1X?+2X?+3X?+4X?+5X?+6X?+7X?+8X?+9X?+10X?=1980求?是多少
f(x)=(x-1)(x-2)(x-3).(x-10) 求f'(9)=?
f(x)=1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+3)(x+4)+.1/(x+9)(x+10) 求f(8)
已知x=1/x,求x^2-6x+9/x-3/x+3/x^2+6x+9
(x-2)(x*x-6x-9)=x(x-5)(x-3),求6x的算术平方根
3^x=2^x,求x.5^(x-1)·10^3x=8^x求x
2(3-x)=9 求x 4(x+0.5)+x=17求x
已知x=9/2 求:[(x^+7x+10)/(x^2+6x+5)]×[(x^3+1)/(x^2已知x=9/2 求:[(x^+7x+10)/(x^2+6x+5)]×[(x^3+1)/(x^2+4x+4)]/[(x^2-x+1)/(x-2)]
2x+3=9,求x
用递归法求y=x-(x*x*x/3!)+(x*x*x*x*x/5!)-(x*x*x*x*x*x*x/7!)+.
x^3+x^10=a0 +a1(x+1)+...+a9(x+1)^9+a10(x+1)10,求a2=?
当x=9/2时,求(x^2+7x+10)/(x^2+6x+5)×(x^3+1)/(x^2+4x+4)÷(x^2-x+1)/(x+2)
设函数f(x)=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10),求f’(1)