1,0,2,2,6,10,()A.10 B.16 C.22 D.28
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MG=C'=C3g=##=#"}te`1ljlH34Ɏ%@|]Mt,tt6>iw$ف 4
逻辑运算中A表示什么 (1) 0 · A = 0 (10) 1' = 0; 0' = 1 (2) 1 · A = A (11) 1 + A = 1 (3) A · A = A (12) 0 + A = A (4) A · A' = 0 (13) A + A = A (5) A · B = B · A (14) A + A' = 1 (6) A·(B·C) = (A·B)·C (15) A
逻辑运算中的A表示什么 (1) 0 · A = 0 (10) 1' = 0; 0' = 1 (2) 1 · A = A (11) 1 + A = 1 (3) A · A = A (12) 0 + A = A (4) A · A' = 0 (13) A + A = A (5) A · B = B · A (14) A + A' = 1 (6) A·(B·C) = (A·B)·C (15
a-2a+3a-4a+5a-6a+7a-8a+9a-10a+11a.+99a-100a=
(3a+5)-{9a-[6a+2-(12a-10)+2(a+1)]}
(3a+5)-{9a-[6a+2-(12a-10)+2(a+1)]
化简[(a³+2a²+4a)/(a³-8)-10/(a²+a-6)]/[1-21/(a²-4)]乘以(a+3)/(a-2)
若a^2-10a+1=0,求a^2+1/a^2和(a-1/a)^2
先化简,再求值[(a^3+2a^2+4a)/(a-2)(a^2+2a+4)]-10/(a^2+a-6)除以[1-21/(a^2-4)]*(a+3)/(a-2),其中a=1/2
先化简,再求值[(a^3+2a^2+4a)/(a-2)(a^2+2a+4)]-10/(a^2+a-6)除以[1- 21/(a^2-4)]*(a+3)/(a-2),其中a=1/2
合并同类项:a-2a-3a+4a+5a-6a-7a+8a+9a-10a-11a+12a+……+2008a+2009a-2010a-2011a
化简1/a(a+10)+1/(a+1)(a+2)+...+1/(a+2009)(a+2010)
解高次方程3a^4一10a^3十12a^2一6a十1=0
a*a+b*b-2a+6b+10=0求a的2004次方+1/b的值
若a^2+b^2-10a-6b+34+0,求a+b/a-b
a-2a-3a+4a+5a-6a-7a+8a+9a-10a-11a.+2008a+2009a-2010a-2011a如何合并同类项?
分式的条件求值已知:a的平方-6a-4=0,求代数式2(a的平方-10a)/(a的平方-4a+4)÷(1-a-(12)/(2-a))
(1) 10^-2×10^0×(-10^5)+10^-1÷(-10)^0 (2) (-a^4)^3-(a^2)^6-a•a^3•(-a^2)^4有俩题啊,
已知a^2-3a-1=0 则a^3-10a的值是