y=log(1/2)(x^2+2x-3) 的递增区间 （1／2是底数）

log 9 X/Y=1/2(log 3 X - log 3 Y) log 9 X/Y=1/4 3log 3 X =2log 3 Y find X and Y log(2x)+log(3y)-log(2z) 怎么化简?log3(x^2-2x-6)=2 log(3x+6)=1+log(x)求解,求每步详...log(2x)+log(3y)-log(2z) 怎么化简?log3(x^2-2x-6)=2 log(3x+6)=1+log(x)求解, 已知log（2）[log（3)(log(4) x)] = log(3) [log(4) (log(2) y)]=0,求x+y的值 函数y=log(1/2)2x+log(1/3)x的单调区间为 [log(4)(2x)][log(2x)(3y)][log(3y)(z)]=log(8x)[(8x)]^2,则z=? log(2x)+log(3y)-log(2z) 怎么化简? log3(x^2-2x-6)=2 log(3x+6)=1+log(x)求解. 2log(m)y-log(m)x-log(m)z 函数y=f(x)=log(1/2)2x+log(1/3)x的单调递减区间 换底公式的使用!为什么 y=log(1/2) X = - log(2)X 若-3≤log(1/2)x≤-1/2,则函数y=(log(2)x－1)(log(2)x－2)的值域为? log 3 (4+x+4y)^2=0 联立 log 2 (x+1)^2=1+3log 2 y^2 求 log(0.5x)(2)-log(0.5x^3)(x^2)=log(0.5x^3)(4) 1/log（2）x+1/log（3）x+1/log（4）x=1,x=? 若log底数2[log底数3(log底数4)]若log底数2[log底数3(log底数4（x）)]=log底数3[log底数4(log底数2(y))]=log底数4[log底数2(log底数3z)]=0,则x+y+z= 求函数 y=LOg(x-1) (-x的平方+2X+3)的定义域 求函数y=log+2的x次方+1/log（3x-2）的定义域 log(X+5)+log(X+2)=1 log（x+5）=log（x）+log（2） log（8）+log（x）=log（24） 2log（x）=log(2x)+log(3)