已知log5(根号6+1)+log2(根号2-1)=a,则log5(根号6-1)+log2(根号2+1)=

已知log5(根号6+1)+log2(根号2-1)=a,则log5(根号6-1)+log2(根号2+1)= 1、计算log5^35+2log1/2^根号2-log5^1/50-log5^14 2、已知log3^7=a,log2^3=b,求log21^28 (log5根号2乘以log7 9)除(log5 3分之1乘log7 3倍的根号4)+log2(根号(3+根号5)—根(3-根号5)) log5(1+√6)+log2(-1+√2)=a.则log5(-1+√6)+log2(1+√2)=?√=根号. 已知log5(√6+1）+log2(√2-1）=a,则log5(√6-1）+log2(√2+1）= 计算log2 6-log2 3,lg5+lg2,log5 3+log5 1/3,log3 5-log3 15 已知x=log2（5）-log2（根号5）,y=log5（3）,z=5^-1/2.则下列关系正确的是?A z log2(log5 x)=-1 (log3^4+log5^2)(log2^9+log2^根号3) 对数算术问题!求下列的值(1)6分之1 log2 64 +2分之1 log8 64 +log3 81(2)lg5分之1-2lg 根号0.2-log5 25*log5 2(3)log5 3分之1+2log2分之1*根号2-log3 27分之1-log5 15分之1(4)(log2 5+log4 0.2)*(log5 2 +log25 0.5)会做的帮下拉 ! 计算log3(1/9)+lg(1/10)+log2(6)-log2(3)+5^[log5(3)] log2^25*log3^2倍根号2*log5^9= log2^5*log3^2倍根号2*log5^9= log2 5*log5 81*log3 4+ln根号e lg(1/4)-lg2(5) 2log5(10)+log5(0.25) 2log2(25)-3log2(64) log2(log2(16) ) log的一道数学题log3 1/64×log4 √5×log1/25 27 √5是根号下5 ×是乘号=log3 2^(-6) ×log2^2 5^(1/2) ×log5^(-2) 3^3=[(-6)×log3 2] ×[(1/2)×(1/2)×log2 5] ×[(-1/2)×3×log5 3]这个是怎么转换的 底数也能放前面吗比如log2^ 求下列各式的值 1）log2 6+log2 3 2)lg5+lg2 3)log5 3+log5 三分之一 4）log3 5-log3 15 log2/log5等于多少