x/3-y/4=1 3x-4y=2 怎么解,用2元1次方程组的解决思路解
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{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1
x^2-4xy+3y^2=(x-3y)(x-y)x^2-4xy+3y^2 怎么分解成(x-3y)(x-y)
(x-y) (x-2y)+(x+2y) (x-3y)-2(x-3y) (x-4y)=
x+y+2(-x-y+1)=3(1-y-x)-4-(y+x-1),x+y=?
先化简 再求值 (2x-y)(y+x)-(x-2y)(2y+x)-(-3y+x)^2其(√x+1)+y^2+4=-4y
化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1
已知x-y=1,求[(x+2y)^2+(2x+y)(x-4y)-3(x+y)(x-y)]除以y的值大神们帮帮忙
已知x-y=1,求[(x+2y)²+(2x+y)(x-4y)-3(x+y)(x-y)]÷y的值
二元一次方程(x+y)/2+(x-y)/3=6,4(x+y)-5(x-y)=2怎么算
[(y-2x)(-2x-y)+4(x-2y)平方]/3y,其中x=1,y=-3
[(2x+y)^2+(y+2x)(y-2x)-2y(4x-y)]/4y,其中x=1/2,y=1/3
先化简,再求值:[(x+y)(x-y)-(x-y)^2+2y(x-3y)]/(-4y),其中x=1,y=-2
9y=3x-(x-1),4(x+y)-(2x+4)=8y
为什么(x-2y)(x+4y)-(x-2y)+3(x+4y)-3=(x-2y+3)(x+4y-1).
4x(x-y)-(2x-3y)(2x-3y) x=1 y=-1
解二元一次方程组:3(x+y)-4(x-y)=4,x+y/2+x-y/6+1x+y/2+x-y/6+1=1
若x+y=4,则多项式1/2(x+y)+4(x-y)-3(x-y)-3/2(x+y)-x+y值是()
若x=-1/4,能否确定代数式(2x-y)(2x+y)+(2x-y)(y-4x)+2y(y-3x)的值?