n趋向无穷大时lim[1/(2*n^2)+3/(2*n^2)+……(2m-1)/(2*n^2))]　其中m为常数

lim (1+1/2n)^n n趋向于无穷大 lim√1+1/n^2 n趋向于无穷大 lim n趋向无穷大3n^3+n^2-3/4n^3+2n+1 lim[n/(n*n+1*1)+n/(n*n+2*2)+...+n/(n*n+n*n)],当x趋向无穷大时,怎么求极限, 紧急：求 lim n*sin(π(n^2+2)^0.5）*(-1)^n,n趋向无穷大； n趋向于无穷大,lim n[ln(n+2)-ln(n+1)], 求lim(1+1/n+2)=n->0的极限?（n趋向无穷大） 证明lim(n/(n^2+1))=0(n趋向于无穷大） lim(n^2(cos1/n-1))(n趋向于无穷大） lim n趋向无穷大 (2^3n-3^2n-1)/(2^3n+3^2n)=? lim n趋向无穷大(3^n+2^n)/(3^（n+1）-2^（n+1）)=? 证明 lim(1-1/2^n)=1 n趋向于无穷大 lim(1-1/2^n)=1 n趋向于无穷大 lim n趋向于无穷大时,1/(n+1)+1/(n^2+1)开2次方+...+1/(n^n+1)开n次方 n趋向于无穷大时,lim（1+a）(1+a^2).(1+a^2n）且|a| lim{(1/n+1)+(1/n+2)+.+(1/2n-1)+(1/2n)}在n趋向无穷大时等于多少谢谢了,大神帮忙啊 用夹逼准则求lim(1/n^2+1/(n^2+1)+...+1/(2n)^2),n趋向于无穷大 lim(1/n+1/(n+1)^2+…+1/(2n)^2) n趋向于正无穷大