[3(m+n)]^ 2-(m-n) ^2[3(m+n)] ^2-(m-n)^ 2 怎么到达下步的=[3(m+n)-(m-n)] [3(m+n)-(m-n)]

[(m-n)^2*(m-n)^3]^2/(m-n)^4 [(m-n)^2*(m-n)^3]^2/(m-n)^4 3m(m-n)-2n(m-n)的平方 因式分解(n-m)^3(m-n)^2-(m-n)^5 （m-n)2(n-m)3(n-m)4化简 （n-m)^3×(m-n)^2-(m-n)^5 计算(m+n)^3-(n+m)(m-n)^2 (m-n)^3(n-m)^2(m-n)=_____ 4m(m-n)^2+4n(n-m)^3 (1),(-m-n)(-m+n) (2),(-m+n)(m-n) 2(m-n)的2次-(m+n)(m-2n)-3n(n-m) 2m-3n-m+2n (m-n)3-(2n-m)3 (3m-n)(m-2n)=() (m+2n)(m-3n) (m-3n)(2m+n) 约分(m-n)^2/(n-m)^3 (m-2n)(-m-n)