y=√2sin(2x+π/4)-1/2cos²x 化简~急用~
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y=sinx+cosx可化成_____?A.2sin(x-π/4);B.2sin(x+π/4); C.√2sin(x-π/4);D.√2sin(x+π/4);
(y')^2 = y^4 - y^2答案是y(x) = 1/sin(∏/6±x),恒为0的不算 其实是通解啦y(x) = C/sin(∏/6±x),C为常数
y=2sin三分之一x y=4sin(x-π/3) y=sin(2x+π/6) y=3sin(1/2x-π/4) 的周期各是多少,
将函数f(x)=sin(2x-π/3)的图像左移π/3,在讲图像上各点横坐标压缩到原来的1/2,则所得的图像的解析式为:A.y=sinx B.y=sin(4x+π/3)C.y=sin(4x-2π/3) D.y=sin(x+π/3)
以y=sin(x+C)为通解的一阶常微分方程是?y=√1-y^2
函数y=(cos x+sin x)/(cos x-sin x)的最小正周期是多少?A.1 B π/2 C 2π D π
y=√2sin(2x+π/4)-1/2cos²x 化简~急用~
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