用数学归纳法证明1+n/2≤1+1/2+1/3+...+1/(2^n)≤1/2+n当n=k+1时,1+1/2+1/3+...+1/2^k+1/(2^k+1)+...+1/2^(k+1)>=1+k/2+1/(2^k+1)+...+1/2^(k+1)>1+k/2+1/2^(k+1)+...+1/2^(k+1)>1+k/2+[2^(k+1)-2^k]/2^(k+1)=1+(k+1)/21+1/2+1/3+...+1/2^k+1/(2^k+1)+...+1
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/06 11:20:47
xSJ@mH|m⇈}R
DѦ5J쿔ff[⣐0̙3gvi=n+NA"۾T$EV8i5iĸZ}T)G{M)R*F/,VXưndeu65oGF5"QC`~d2F_3zߒ1T;"@e;+)vhn3òJg1 ZEÚx&dhc.V#"kb3v"x
[V?WnoDY=3Ot,4Lei;kOi?l(as$һ3$
%
Gk_l
Y,'.J@ 8wz?1-<~DeS#=FSoI qYGmֹde+4دg^ᗐK