200*20+(x-20)40=20*200*0.9+40X*0.9
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/09 01:47:07
x)32022֨52415q
,M"@MR>1l6F 1
v"
20/(x-20)=(2x-40)/(x+40)
2x/40%=x+20x=?
X+(X+40)+(2X-20)=320
4x-2(x+20)=200
(40-X)(20+2X)=1200
(20+2x)(40-x)=1200
(20+2x)(40-x)=1200
(40-x)(20+2x)=1200
(40-x)(20+2x)=1200
(20+2x)(40-x)=1200
(40-x)(20+2x)=1200
(40-x)(20+2x)=1200 800+80X-20X-2x^2=1200 -2x^2+60X-400=0 x^2-30X+200=0 (X-10)(X-20)=0 X-10=0 X-20=0(X-10)(X-20)=0 40-x)(20+2x)=1200 800+80X-20X-2x^2=1200 -2x^2+60X-400=0 ^2-30X+200=0 (X-10)(X-20)=0
2(40-2x)(20-x)+2x(20-x)+2x(40-2x)=550怎么解
(X+X*20%)-[(1200-X)-(1200-X)*20%]=40%
X+X*20%-(1200-X)-(1200-X)*20%=40%
x/(x+200)=20%
x+20%x =40
x+(x-20)=40