(1)(x-y)^2-(2x+y)(y-2x) (2)(x+y)(y-x)( )=x^4-2x^2 y^2+y^4
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(x-y)(x-y)2(y-x) (x+2y-?)(x-2y+?)
对于(y一撇)y`=y/x(y-1)求导,我求的结果是y``=-y^2-y`x+y/x^2(y-1)^2 怎么不对啊,我的求导过程是:y`x(y-1) - [x(y-1)]` y y`xy-y`x-(y-1+xy`)y -y^2-y`x+yy``=-------------------------=----------------------=-----------------x^2 (y-1
(x-2y)(x+y)+(x+y)计算
计算:(x-y)^2-(x+y)(x-y)
2(x-y)²-3(x-y)(-y-x)
(x-y/x+2y)³
计算:1/(2x) - 1/(x+y)((x+y)/(2x) - x - y)
化简1/2x-1/x+y(x+y/2x-x-y)
计算2x/1-x+y/1·(2x/x+y-x-y)
1/2x-(x+y/2x -x-y)÷(x+y)
{(x²+y²)-(x-y)+2y(x-y)}/4y
[(x+2y)²-(x+y)(x-y)-7y²】÷(2y)
分式的加减:[(x/y-y/x)除以(x+y)+x(1/y-1/x)]除以1+x/y,其中x=5,y=2
(x/x+y +2y/x+y)乘以xy/ x+2y除以(1/x+1/y)(2)(3x^2/4y)^2乘以2y/3x+ x^2/2y^2除以2y^2/x
化简 x-y+(2y²)/(x+y)
y'=(y/x)^2+y/x+4微分方程
已知2x-y=0,求分式【1+(3*y*y*y/x*x*x-y*y*y)】/【1+(2y/x-y)】的值注:x*x*x-y*y*y=(x-y)*(x*x+xy+y*y)
若|x+y-1|+(x-y-2)²=0,求代数式(x+2y)(x-2y)-(2x-y)(-y-2x)的值.