[1÷(4.1-4.09)]x 0.49+0.51
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/10 15:18:44
xQMN@42MpARq0D7.ICcjʯUPcZ01R,Ȃ0oYq_c&b~'[lLkۇ+Ddt!rVn16Gd,S1|oL{o#RM:ףN<3+b z0/Pw:qבa9j]ӰO'槠V# `0-qFB(Ą7d 2ƳSBi0Aa
ZfFUxB6{QM/$_/OJMvɧ| T
[1÷(4.1-4.09)]x 0.49+0.51
x-1/x÷(x-1/x)
分式计算及解方程1.[(3x)/(x-2)-x/(x+2)]÷x/(x²-4)2.(3-x)/(x-4)+1/(4-x)=13.2a/(a²-4)+1/(2-a)4.1/(x-3)-(x+3)/(x²-1)·(x²-2x+1)/(x²-9)5.2x/(x+1)+1/x=26.x/(2-x)-3/(x-2)=4
化简(x^2-2x+1)/(x^2+1)÷(x-1)/(x^2+x)-x
[x^2+2x-8/x^3+2x^2+x]÷[(x-2/x)×(x+4/x+1)]化简[x^2+2x-8/x^3+2x^2+x]÷[(x-2/x)×(x+4/x+1)]化简
【{x²-4x+4/x²-4}-x/x+2】÷x-1/x+2
(x+1-1/1-x)÷(x-x²/x-1) (x-4/x-x-6+ x+2/x-3)÷x+1/x-3
[1-x+(x-1/x)]÷[1-(1/x+1)]
(x-x²/x+1)÷(1-x²-1)
计算:( x-1)/x÷[x-(1/x)]
x/x^2-2x÷(x^2-4)^-1
(x²-x+1)÷(x²-x-1)=(x²+x)÷(x²+x-2)解方程
x²-1/x²-2x+1÷x+1/x-1 X 1-x/1+x
X×X-3X+1=0求分式X×X÷〈X×X×X×X+3X×X+1〉
计算:2x/(x-2)(x+1)÷(1-x/x+1)-x²+2x/x²-4?
X^2-3X-2=0,求( x - 2x-1/x )÷(x-1)/(x^2-2x)
(2x-6)/(x^2-9)+(x^2+2x+1)/(x^2+x-6)÷(x+1)/(x-2)
[(x+2)/(x²+2x)-(x-1)/(x²-4x+4)]÷(x-4)/x