若cos(θ/2)=3/5,sin(θ/2)=﹣(4/5),则角θ的终边所在的直线方程为?怎么求啊,..看懂第一时间采纳...
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/17 09:26:05
x͐JP&L1HYUIrS;mĂj&EBaj6OY
]7=s4(J|=oCXGVW+'C{,nrDG+ q4Ӝ_>@#S@iסq\ U8_.Mg(j'(ihna_>U6N1H9Y^@qv!mt]Q$J
h|uV77ԝZTۤ`V4`ye{tK)T5h=>7bW
若sin θ+cos θ/sin θ-cos θ=2,则sin θcos θ的值是请问如何判断sin θcos θ的正负
若(sinθ+cosθ)/(sinθ-cosθ)=2,则sin(θ-5π)*sin(3π/2-θ)等于?
若sin(θ-π)=2cos(2π-θ)求(1)sinθ+5cosθ/sinθ-3cosθ (2)sinθcosθ的值
已知tanΘ=2,计算①sinΘ+2cosΘ/5cosΘ-sinΘ②1/sinΘcosΘ-cos∧Θ
若[sin(π-θ)+cos(2π-θ)]/[cos(5π/2-θ)+sin(3π/2+θ)]=2,求sinθ*cosθ的值若[sin(π-θ)+cos(2π-θ)]/[cos(5π/2-θ)+sin(3π/2+θ)]=2,求sinθ*cosθ的值
2sinθ+cosθ/sinθ-3cosθ=-5,求cos2θ+4sinθ
已知(4sinθ-2cosθ)/(3sinθ+5cosθ)=6/11,求5cos^2θ/(sin^2θ+2sinθcosθ-3cos^2θ)
请会的大哥大姐多多指教.已知sinθ=(√5-1)/4(1)求(sinθ-cosθ)/(sinθ+cosθ)+(sinθ+cosθ)/(sinθ-cosθ)的值.(2)已知5sinθ+12cosθ=0,求(sinθ+9cosθ)/2(2-3sinθ)的值.
求值:已知sinθ+cosθ=1/5,已知θ∈(0,π).求(1)sinθ*cosθ(2)sinθ-cosθ(3)tanθ
若满足sinθ-2cosθ/sinθ+3cosθ=2,则sinθ*cosθ的值等于多少?
sin(π-θ)+cos(2π-θ)/cos(5π/2-θ)+sin(3π/2+θ)=2,则sinθcosθ=______
已知θ为第三象限角,1-sinθcosθ-3cos^2=0则5sin^2θ+3sinθcosθ=?
(1)已知sinθ+2cosθ=0,计算:2sin^θ-3sinθcosθ+5cos^θ=?
已知sinθ+2cosθ=0,计算2sin平方θ-3sinθcosθ+5cos平方θ
若sin θ-cos θ 分之sin θ+cos θ=2 则sin θcos θ 是
若(sinθ+cosθ)/(sinθ-cosθ)=2,则sinθcosθ的值是
2/sinθ+3/cosθ(0
(sinθ+cosθ)/(sinθ-cosθ)=2,则sin(θ-5π)*sin(3π/2-θ)=