y=2sin(2x+π/3) (-π/6≤xπ/6)求其值域 π是圆周率(Pai)解∵(-π/6≤xπ/6)∴0
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/11 08:06:34
xWRW-]Y|CT Yyaonx^ `*b=0$?;3+~!oF2ĕJqՀft}oO/'ԣ~w8:]]*׆ڪSi*v&~5{~M8oowoP䇟 zVmjL_@C줖x}_|
A-hv9Dƹ[]V~
y 4R}JĻk/M+1([j]Xv"f}o
oCU^bW~''8Q)&R\FP#by /$mjgB SrǷc R ANC9x(x]GDoD?gF=s4aXQC~`A^[`Ib;XT(^0
31+
! 0B~4r;ӠƊ`2[MjEhGf8$Jn@a@>߆+^ujˌ٣.^$eM@fn`;K2Z/4#*%Pp~<|8S.UtƷw٫·g6rt9{woi0&YF (#DY mft}h{]{т:,̪7ri,}24pIo{G`zq47#&dRȉ]!/ nYMZPp _h^Cwa]\LqJ:#a[ev`61PD@@7"L=όܼ} r~e#0S;)ۅ0+m{!Kۉ}*q|:<#}>}a NݛCQCNb&3}!^L*p%zB殉Xp[KUv#YY?_8d^8@+iJjaO;".+uʙħGڬ懋E)qty@3P
].J^g`䘳^KrdBBG6E""<+}I6Q=pujm0> 3h -'-q9
判断单调性 y=sin(x-π/6) y=sin(-2x+π/3)
y=12sin(2x+π/6)+5sin(π/3-2x)最大值
y=12sin(2x+π/6)+5sin(π/3-2x)的最大值
函数y=2sin(π/3-X)+sin(π/6+X)的最大值
y=2sin三分之一x y=4sin(x-π/3) y=sin(2x+π/6) y=3sin(1/2x-π/4) 的周期各是多少,
y=sin(x-π/6) 和 y=1/2sin(π/3-2x) 的单增区间,
y=sin(x+π/6)如何移动得到y=sin(2x+π/3)
y=sin(x+π/6)如何移动得到y=sin(2x+π/3)用两种方法啊
1.y=sin(-X+π/6)2.y=cos(-2X+π/3)
求下列函数周期 y=3sin(x/4) x属于Ry=2sin(2x-π/6)
y=sin(x+π/3)sin(x+π/2)化简
周期y=sin(x+π/3)sin(x+π/2) 的最小正周期是多少
周期 最值 单调区间y=sin(2x+π/3) y=2sin(2x+π/6)-2 y=sin(π/3-2x) y=tan(π/3-2x)
已知sinx=3/5,x∈(π/2,π),求【sin(x+y)+sin(x-y)】/【cos(x+y)+cos(x-y)】的值
y=2sin(x/2+π/6),x属于R y=-6sin(2x-π/3),x属于R 写出振幅,周期,初相
函数y=12sin(2x-π/6)-5sin(2x+π/3)的最大值
函数y=2sin(2x+π/6) ( -π
y=sin(π/3-π/2x)的周期