数列{an},a1=1,a(n+1)=c-1/an.c=5/2,bn=1/(an-2)求{bn}的通项公式.1/[a(n+1)-2]=2an/(an-2)下一步怎么写?1/[a(n+1)-2]=4/(an-2)+2所以 b(n+1)=4bn+2都不懂怎么来的
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