若x,y,z均不为0,且x+y+z=0,证明:√(1/x^2+1/y^2+1/z^2)=|1/x+1/y+1/z|
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/26 03:52:46
x){ѽBR';zedǔ
J*[{g֣YtWiWɪ8#MHįI*ҧv64q%XD-^m#}JMUY*4&S[5@hWTƂ> *[
J nQ@T~cɋ};ix`:OMڱ/킇6yvx
已知x、y、z都不为0,且4x-3y-3z=0,x-3y+z=0,求x:y:z
已知4x-3y-6z=0 ① ,x+2y-7z=0 ②,且x,y,z均不为0,求3x+2y+z÷x+2y+3z的值
已知4x-3y-6z=0 ① ,x+2y-7z=0 ②,且x,y,z均不为0,求3x+2y+z÷x+2y+3z的值
已知x,y,z均不为0,且满足方程组x+y-z=0,2x-y-5z=0试求2x+y+3z/3x-y-z
已知x,y,z均不为0,且满足方程组{x+y-z=0,①2x-y-5z=0.②试求(2x+y+3z)/(3x-y-z)值.
若x,y,z均不为0,且x+y+z=0,证明:√(1/x^2+1/y^2+1/z^2)=|1/x+1/y+1/z|
已知x,y,z均不为0,且满足方程组x+y-z=0,①2x-y-5y=0.②试求2x+y+3z/3x-y-z值.
已知(X+Y)/Z=(X+Z)/Y=(Y+Z)/X,且XYZ≠0,则(X+Y)(Y+Z)(Z+x)/XYZ的值为
已知:(x+y)/z=(x+z)/y=(z+y)/x,且xyz不等于0,则分式(x+y)(x+z)(z+x)/xyz的值为?
若xy-z=0,且(y+x)/x=(z+x)/y=(y+x)/z,求[(y+z)(z+x)(x+y)]/xyz的值?
若xy-z不等于0,且(y+x)/x=(z+x)/y=(y+x)/z,求[(y+z)(z+x)(x+y)]/xyz的值?
已知x,y,z都不为0,且满足4x-3y-3z=0,x-3y+2z则,x:y:
若xyz不等于0,且(y+z)/x=(z+x)/y=(x+y)/z,求(y+z)(z+x)(x+y)/xyz的值?
若xyz不等于0,且满足(y+z)/x=(x+z)/y=(x+y)/z,求(y+z)(x+z)(x+y)/xyz的值
若xyz不等于0,且满足(y+z)/x=(x+z)/y=(x+y)/z,求(y+z)(x+z)(x+y)/xyz的值
已知3x-2y-5z=0,2x-5y+4z=0,且x,y,z均不为0,求3x*x+2y*y+5z*z/5x*x+y*y-9z*z的值.
已知 (x+y-z)/z=(x-y+z)/y=(y+z-x)/x,且xyz≠0,求代数式 ((x+y)(y+z)(x+z))/xyz
若x、y、z均不等于0,且2x+y-z=0 x+8y+2z=0,则x:y:z=?