∫y √{y+5} dy=?

∫y √{y+5} dy=? dy/dx-y=xy^5 y=(1+cosx)^5 求dy 求dy/dx=(x-y+5)/(x+y-2) ∫（siny/y）dy dy/dx-y=cosx dy/dx-y=xy5 dy/dx=x+y 为什么y'=dy/dx? y=dy/dt是什么意思, y=sin2x,求dy y=lncosx,求dy y=lncosx 求dy y=3in2x,dy Y=XsinX 求dy 高数下,求大神改变二次积分次序,∫[2,0]dy∫[√8-y^2 ,√2y] f(x,y)}dy= ∫y*[e^(-y)]dy 求详解 ∫[(-y^2)*e(-y^3)]dy