计算Ω∫∫∫(x^2+y^2+z^2)dV,其中Ω是球面x^2+y^2+z^2=1所围成的闭区域

计算∫s∫（x+y+z)dS.S:x^2+y^2+z^2=4,z>=0 计算（x-y-z)^2 计算三重积分∫∫∫Ω(x^2+y^2)dv,Ω={(x,y,z)|(x^2+y^2)/2≤z≤2} 计算:x^2/(x-y)(x-z)+y^2/(y-x)(y-z)+z^2/(z-x)(z-y) 计算(2x+y+z)(2x-y-z), 计算(x+2y-z)(2y+z-x) 计算(x-2y+z)(z-x-2y), (x一2y+z)(-x+2y+z)(计算) 计算:(x+2y-z)(x-2y-z) 计算(x+2y-z)(2y+z-x) 计算：(x-y-z)^2-(x-y+z)^2 (x+2y-z)(x-2y-z)计算过程 计算：(x+2y-z)(x-2y+z) 计算:(y-x)(z-x)/(x-2y+z)(x+y-2z)+(z-y)(x-y)/(x+y-2z)(y+z-2x)+(x-z)(y-z)/(y+z-2x)(x-2y+z) 计算I=∫∫x(1+x^2z)dydz+y(1-x^2z)dzdx+z(1-x^2z)dxdy其中∑为曲面z=√x^2+y^2(0 计算三重积分∫∫∫zdv,其中Ω是有曲面积分z=√(2-x^2-y^2)和z=x^2+y^2 计算三重积分∫∫∫(|x|+|y|+|z|)dv,其中Ω:x^2+y^2+z^2≤a^2,哪位大师来解下, 计算∫∫（S）(x+y+z)dS,其中S为曲面x^2+y^2+z^2=a^2,z>=0