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|x-1/i|
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main(){int x,i;for(i=1;i
为什么(2-3i)x(1+i)=5-i
不等式X+I2x-1I
(x-1-√2i)(x-1+√2i)(x-2+√3i)(x-2-√3i)
N={x||x-1/i|
N={x||x-1/i|
N={x||x-1/i|
虚数 化简i^(7x+ 2)还有i^(6x-1),i^(14x-11)
证明:e^pi*i=-1即(e)^(x*i)=cos(x)+i*sin(x).
|X+i|
|x-i|
(1+2i)(x+yi)=4+3i (x-2y)+(y+2x)i=4+3i
I 1 3 0 I I 7 I I 0 1 -1 I X= I 2 I求X.大哥大姐,用矩阵的初等变换写~I 2 1 5 I I 4 I
fortran程序,subroutine solvereal::i,x,y,mreal::h(i),d(i),a(i),dy(i)h(i)=(1+2*(x-a(i))/(a(i+1)-a(i)))*(((x-a(i+1))/(a(i)-a(i+1)))**2)d(i)=(((x-a(i+1))/(a(i)-a(i+1)))**2)*(x-a(i))m=y(i)*h(i)+dy(i)*d(i)end subroutine solveprogram mainreal::i,sreal::a(
matlab程序高斯消元法的,X(i)=(B(i,n+1)-B(i,i+1:n)*X(i+1:n)')/B(i,i),
X/6-1=X/10+I,X等于几