(1 +3 +5+ ...+2011)-(2 +4 +6 +...+2010)=?
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/02 20:34:24
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-5^2011×0.2^2011×(-1)^2011
1+3+5+...+2011
2011-1/2×2011-1/3×(2011-1/2×2011)-...-1/2011×(2011-1/2×2011-...-1/2010×2011)
计算 (-1)+(+2)+(-3)+(+4)+(-5)+…+(-2010)+(+2011)
一道数学题:1/(1*3) + 1/(3*5) +1/(5*7)+ …… 1/(2009*2011)= 1/(1*3) + 1/(3*5) +1/(5*7)+ …… 1/(2009*2011)=
(-1)+(+2)+(-3)+(+4)+(-5)+...+(-2011)+(+2012)
计算:(+1)+(-3)+(+5)+(-7)……+(+2009)+(-2011)
(运用拆项法):(-2011 5/6)+(-2010 2/3)+4022 2/3+(-3 1/2)
计算:(1+1/3+5/1+7/1+...+1/2009+1/2011)(1/3+1/5+1/7...+1/2011+1/2013)-(1+1/3+1/5+1/7+...+1/2011+1/2013)(1/3+1/5+1/7+...+1/2009+1/2011)
(-5)^2-0^+(-4)^2011*(-1/4)^2011
计算:(+1)+(-3)+(+5)+(-7)+……+(+2005)+(-2007)+(+2009)+(-2011)
1+(-2)+3+(-4)+5+(-6)...+2011+(-2012)等于几
(-1/10)^-2+(-3)^0+(-0.2)^2011*(-5)^2011
计算:(+1)+(-3)+(+5)+(-7)+.+(+2009)+(-2011)=
(+1)+(-2)+(+3)+(-4)+(+5)+(-6)+…+(+2007)+(-2008)+(+2009)+(-2010)+(+2011)=?
(+1)+(-3)+(+5)+(-7)一直加到+(+2009)+(-2011)
计算:(1-1/2)(1/3-1)(1-1/4)(1/5-1)……(1-1/2010)(1/2011-1)
计算1+3+5+7+...+2009+2011