设函数f (x)=sin(ωx+φ)cos(ωx+φ)的最小正周期是2,且当x=2时取最大值,则φ的设函数f (x)=sin( ωx+φ)cos(ωx+φ)的最小正周期是2,且当x=2时取最大值,则φ的

设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f x=SIN(2X+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(0 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+ φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+ φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数 f(x)=sin(2x+y),(-π 设函数f(x)=sin(2x+∮)(-兀 1.设函数f(x)=sin(x+fai)(0 设函数f(x)=sin(wx+t)(-π/2 设函数f(x)=sin(wx+t)(-π/2 设函数f（x）=sin(ax+q) (-兀