13x+11y=129 11x+13y=135 解方程组
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{x=y-3 {x+y=11 {2x+y=13 {3x-2y=81.{x=y-3 {x+y=112.{2x+y=13 {3x-2y=8
x+x+x+x+y=40 x+y= 13x=y=
{x-y=2,4(x-y)-y=5 {4x-3y=11,2x+y=13
13x+11y=129 11x+13y=135 解方程组
[(y*y*y-y)/(xy+1)*(xy+1)-(x+y)*(x+y)]/[(x+y)*y/(x+1)]其中x=-11,y=1/12,化简再求值.
4(x-y)-3(x-y)=9 5(x-y)+2(x-y)=11
3(x+y)-4(x-y)=11,2(x-y)+5(x+y)=27
3(x+y)-2(x-y)=11 4(x+y)+3(x-y)=9
6(x+y)的平方-11(x+y)(x-y)+3(x-y)的平方=?
若x,y是正整数,且满足x(x+y)-y(x+y)=11求x+y的值
若x、y为正整数,且满足x(x+y)-y(x+y)=11,求x,y的值
求解二元一次方程组(要详细的步骤)2x+y=13 3x+2y=247x+3y=69 2x-y=162x-y=7 x+2y=11
50=11+x+y=7+x+z=y+13+z x=?y=?z=?
4x+9y=12 3y-2y+5z=11 5x-6y+7z=13 求:x y z等于多少
13X+11Y=1240,
解下列方程组{x+y-z=9;y+z-x=13;z+x-y=11}要过程
x+y=11,x+z=8,y+z=13求x ,y,z各是多少?
x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2