抛物线y=ax-3ax+b经过A(-1,0),C(3,-2)两点,与y轴交于点D,与x轴交于另一点B.明天早上要答案!若直线y=kx+1(k≠0)与x轴交于H与DC交于T,且若直线y=kx+1(k≠0)将四边形ABCD面积二等分,求k的值过点E(1,1)作
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/08 05:36:24
xUKO"Y+;MW@/f&I;-Il(-tQѴ##uOUݺbdd:y~|K|d[55מ/ڭ˄'T25L?{0sk\3Y[
)3-:f;Je9etKh};pjr$+fg/gκ^N4JNI˙}VcaWtʦ~(FA@OAuvnD2) ݧF8[l "SsJ^p:_֩[Ul~}K~dz@ 'J&YSX7MPF)pǫ7A{/<=JDQEiy~K@vr`
|^]Z2]Tn;ea UB͆G8qЙYaM(;jpufZ'ZQ}nnB̭sXֈ*tڍUbj pדU.rY*"S]ޫj:rxlm)n~P w]f)KG\{+utJRY(cIf'2Y"Z-R>4$!EmL9ߒ+EjqOW"7'1>opUHݢd1SYs1SdIcdH0A!6ka~Ch9iUyxT/g(/pbјg6)x<㈣yIXa ʱNxD
EU_&NgCK~@8V8> X
/:7qD.b<"B