已知函数f(x-1)是偶函数,且x<-1时,f'(x)>0恒成立,又f(2)=0.则(x+1)f(x+2)的解集为a,(-∞,-2)∪(4,+∞)b,(-6,-1)∪(0,4) c,(-6,-1)∪(0,+∞)c,(-∞,-6)∪(4,+∞)
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