3/((x-2)(x+1))-(1/(x-2))2/(a²-1)+1/(a+1)x/(2-x)-(4-x²)/(x²-4x+4)
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请问这道题咋做 :(x)X (x+1) X (x+2) X (x+3) =360
(x-1)^3(x+1)(x-2)/(x+4)
x(x+1)(x+2)(x+3)+1 (换元法)
计算 x(x+3)-(x-1)(x-2)
化简:x(2x+1)-x(x-3)
(x+2)(x-2)+16 (x-1)(x-2)+3x(x+3)-4(x+2)(x-3)(x+2)(x-2)+16 (x-1)(x-2)+3x(x+3)-4(x+2)(x-3)
(x+1)(x+2)(x+3)(x+4)+1(x+1)(x-2)(x+3)(x-4)+25
计算(x*x+4x+5)/(x+2)-(x*x+6x+10)/(x+3)+1
x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4
(x-1/x+1 - x+1/x-3 )除 2/x²+2x+1
x(x平方-1)+2X平方(X+1)-3X(2X-5)帮个忙
【(Xˇ2-X)/x】 ·【 x/(X+1)】+【(3x+1)】
[x(x+1)+x平方(x-1)]+(-3x)
x{x+1}{x-1}}x-2}{x-3}-40