x+y+z=3200 (2/3)x+(3/4)y+(4/5)z=2400 (4/5)x+(3/4)y+(2/3)z=2320这道3元一次方程怎么解?
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/28 13:58:27
xRNP.[him&-~~!)] #C1Fho+~i&.teΜ33)#:%aeqFEe"JK$IiBX_oxC{njo)OW 1A'ݞ7\;9s`dbۗ4"_FT U$(V3BR !Sߖx\yjKޭ)K]c@*maAI7\uRVӠ'KK$T&. a%MCB
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
证明 :x/(y+z)+y/(z+x)+z/(x+y)>=3/2其中 x,y,z>0
x/2=y/3=z/5 x+3y-z/x-3y+z
x+2y=3x+2z=4y+z 求x:y:z
x+y/2=z+x/3=y+z/4 x+y+z=27
若x+y+z=3y=2z,则x/x+y+z=?
已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值
已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值
已知x-y/x+y=y+z/2(y-z)=z+x/3(z-x),求证8x+9y+5z=0THX..
已知x,y,z 大于0,x+y+z=2,求证 xz/y(y+z)+zy/x(x+y)+yx/z(z+x)大于等于2/3
X=3z X+y+z=12 X+2y-2z=10
2x+z=10 x+y-z=4 3x-y-z=0
(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=?
如果|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0求x,y,
x+y+z=6 x+2y+3z=14 y+1=z
X/10=Y/8=Z/9,则X+Y+Z/2Y-3Z
x=y/z=z/3,x+y+z =12,求2x+3y+4z是多少,