|z-(2+3i)|
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|z-(2+3i)|
已知|z|+z=2+3i,求复数z
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已知复数Z.=3+2i 复数z满足Z.*z=3z+Z.则复数z等于?
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已知z∈C,且z+3+4i=z(2+i),求z
(2)f(z)=z^2/(z^2+1)(z^2+9),求Resf(z)(z=i)和Resf(z)(z=3i)
f(z)=z^2/{(z^2+1)*(z^2+9)}求Res(z=i)f(z)和Res(z=3i)f(z)
f(z)=z^2/(z^2+1)(z^2+9),求Resf(z)(z=i)和Resf(z)(z=3i)
Z(2-3i)=6+4i 求|Z|,
f(z)=2z+z'-3i f(z'+i)=6-3i,则f(-z)=?z',z是复数!
复数z=[(1+i)^2+3(1-i)]/(2+i),若z^2+a/z
复数z=[(1+i)^2+3(1-i)]/(2+i),若z^2+a/z
复数z=[(1+i)^2+3(1-i)]/(2+i),若z^2+a/z
在复数范围内解方程|z|^2+(z+z拔)i=3-i/2+i
(2-3i)z=(-1+i)z+2-i 求|z|