求值,2sin60°+3tan30°+tan45° (要解题步骤)
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求值:3tan30°-2tan45°+2sin60°+2cos60°
求值,2sin60°+3tan30°+tan45° (要解题步骤)
3tan30°+2sin60°-2tan45°
计算:sin60°+3-tan30°-(cos45°-2)^0
3tan30°-tan45°+2sin60°
2sin60°+4cos45°+3tan30°等于?
3tan30°-tan²45°-2sin60°
2cos60°+tan30°-sin60°
3tan30°-tan45°+2sin60°=?3tan30°-tan45°+2sin60°=?
2sin60°-(根号2)cos45°-3tan30°+tan45°计算
2sin30°·cos45°-(sin60°)负二次方+根号3tan30°
3tan30°-cot45°+2sin60°+cos60°=?
(π-2010)°+(sin60°)^-1-|tan30°-根号3|+2
tan30°+sin60°+cos45°=?
tan30°sin60°-cot45°=?
sin60减去3tan30加2cos45sdu
(1)1—2sin30°cos30°(2)3tan30°—tan45°+2sin60°(3)1+sin60°分之cos60°+tan30°分之1
(tan30°+tan45°)/(1-tan30°tan45°)-2sin60°-sin^2 40°-cos^2 40°