(0.5a^2+ab+0.5b^2)÷（a+b)=_____

a^2+ab+b^2-a-b+0.5求最大值 a+b/2ab 2AB/A+B a+b/2ab (0.5a^2+ab+0.5b^2)÷（a+b)=_____ 计算：(1/4a^2b)×(-2ab^2)÷(0.5a^4b^5) -5a(a^2b-ab^2)÷ab (ab(a^-2ab)-a^2b(a-3b))÷（3a^b） 怎么推导(a^2+b^2)/2>=((a+b)/2)^2和(ab)^0.5>=2ab/(a+b) 3ab{2ab+3(ab-0.5a的2次方b)} ab—2{ab—[3a²b—（4ab²+0.5ab)]—4a²b}—3ab² 先化简,在计算 ab-｛2ab-2［3a^b-(4ab^+0.5ab)-6a^b］｝-3ab^其中先化简,在计算ab-｛2ab-2［3a^b-(4ab^+0.5ab)-6a^b］｝-3ab^其中a=-1,b=3. 计算：a2-2ab/-ab+b2÷(a2/a-b÷2ab/2b-a) (a^2b-ab-a+1)/(ab^2+3ab-b-3)÷(a^2+a_2)/(b^2+b-6) 计算(a+b)/(ab-b^2)÷(ab+b^2)/(a-b)^2= 化简:3a²-【2ab²-2(-a²b-2(-a²b+4ab²)】-5ab²,其中a=-2,b=0.5, (a^2-2ab)/(-ab+b^2)÷[a^2/(a-b)÷(2ab)/(2b-a)] 先化简,再求值:2ab-[一a^b-(ab^-2ab)+(3a^b+4ab^)] 其中a=—2,b先化简,再求值:2ab-[一a^b-(ab^-2ab)+(3a^b+4ab^)]其中a=—2,b=0.5