1/sin(x)+4/cos(x)=7*sin(x)cos(x) x为0到180度闭区间 求x
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求证(cos^2 x-sin^2 x)(cos^4 x+sin^4 x)+1/4 sin 2x sin 4x=cos 2x
急,matlab解非线性方程组用什么函数呢 方程如下所示:(cos(x(1))*cos(x(3))-sin(x(1))*cos(x(2))*sin(x(3)))*(194-x(4))*x(7)+(cos(x(1))*sin(x(3))+sin(x(1))*cos(x(2))*cos(x(3)))*(145-x(5))*x(7)+sin(x(1))*sin(x(2))*x(6)*x(7)-1=0;(-sin(x(1
证明一个sin&cos的等式证明 1+sin^2(x)+sin^4(x)+sin^6(x)=[1-sin^8(x)]/[cos^2(x)]
1/sin(x)+4/cos(x)=7*sin(x)cos(x) x为0到180度闭区间 求x
求证(3-sin^4 x-cos^4 x)/2cos^2 x=1+tan^2 x+sin^2 x
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f(x)=(6sin^4x-7sin^2x+2)/(sin^2x-cos^2x)
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cos x /sin x=
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若sinx+sin^2x=1,则cos^2x+cos^4x=?
求函数y=7-4sin(x)cos(x)+4cos^2(x)-4cos^4(x)值