X+Y=-1,则X^4+5x^3y+x^2y+8x^2y^2+XY^2+5XY^3+Y^4的值等于多少
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若2x-3y+4=0则x(x*x-1)+x(5-x*x)-6y+7
化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1
若x+y=4,则多项式1/2(x+y)+4(x-y)-3(x-y)-3/2(x+y)-x+y值是()
(x+y-5)*(x+y-5)+(x-y+3)=0 x*x-y*y
已知:3x-5y=0,求x/y,x-y/y,x-y/x
(5x+3y)(3y-5x)-(4x-y)(4y+x)=
{3(x+y)+3(y+x)=1,3(x+y)+4(y-x)=-1
{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1
已知x/5=y/3,则(x/x+y)+(y/x-y)-(yxy/xxx-yxy)
4(x-y)-3(x-y)=9 5(x-y)+2(x-y)=11
3(x+y)-4(x-y)=11,2(x-y)+5(x+y)=27
3(x+y)+2(x-y)=36 4(x+y)-5(x-y)=2
(x-y)/(x+y)=3求( 3x-2y-1)/(x+y-5)
{x+y=1 ,xy=-6{x(2x-3)=0,y=x²-1{(3x+4y-3)(3x+4y+3)=0,3x+2y=5{(x-y+2)(x+y)=0,x²+y²=8{(x+y)((x+y-1)=0,(x-y)(x-y-1)=0
先化简再求值(x-y)(x-2y)+(x-2y)(x-3y)-2(x-3y)(x-4y) x=4 y=5
已知x*x+4x+y*y-2y+5=0,则x*x+y*y=?
x+y+2(-x-y+1)=3(1-y-x)-4-(y+x-1),x+y=?
{(x+y)/2+(x-y)/3=1,(x+y)-5(x-y)=2.求x=?,y=?