一直数列{an}满足a1=0,an=（an-1 +4）/(2an-1) ,求 an一直数列{an}满足a1=0，an=（a{n-1} +4）/(2a{n-1}-1) 求 an（其中a{n-1}表示第n-1项）

数列an满足an+1=根号(an^2+1)+an,a1=a>0,求an通项公式 一直数列{an}满足a1=0,an=（an-1 +4）/(2an-1) ,求 an一直数列{an}满足a1=0，an=（a{n-1} +4）/(2a{n-1}-1) 求 an（其中a{n-1}表示第n-1项） 数列{an)满足an=4a(n-1)+3,a1=0,求数列{an}的通项公式 数列[An]满足An+1-An+3=0,且A1=-5.求An. 已知数列满足a1=1/2,an+1=2an/(an+1),求a1,a2已知数列满足a1=1/2,a(n+1)=2an/(an+1),求a1,a2;证明0 已知数列{an}满足a(n+1)=an+n,a1=1,则an= 数列{an}满足a1=a,an+1=1+1/an.若3/2 已知数列{an}满足a(n+1)=an+lg2,a1=1,求an 数列[An]满足a1=2,a（n+1）=3an-2 求an 数列{an}满足a1=2,a(n+1)=2an+n+2,求an 数列an满足a1=1,a(n+1)=an/[(2an)+1],求a2010 数列An满足A1=0,A(n+1)=(An-√3)/(√3An+1)则A2009= 1.一直{an}中,a1=1,an+1/an=1/2,则数列的通项公式为?2.已知数列{an}满足a1>0,且an+1=（n/n+1）*an,则数列{an}是一个怎么样的数列（递增?递减?常数列?摆动数列?）3.数列的项数是无限的吗? 数列{An}满足a1=1/2,a1+a2+..+an=n方an,求an 已知数列{an}满足,a1=2,a(n+1)=3根号an,求通项an数列{an}满足:an>0,且根号下Sn=an+1/4,求通项an 数列an满足a1=0,An+1=an+2n求a2009 数列an满足,a1=8且8an+1an-16an+1+2an+5=0 已知数列an满足a1=1,1/an+1=根号1/an^2+2,an>0,求an