(1)x+3
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[x(x+1)+x平方(x-1)]+(-3x)
解九宫格题目(X为未知数)9 X 2 X 7 X 8 X XX X 4 X X 9 X 6 X1 3 X 5 X X X X 24 X X 8 5 X X 1 XX 8 9 4 X 1 6 7 XX 1 X X 3 6 X X 88 X X X X 2 X 3 6X 5 X 6 X X 9 X XX X 7 X 4 X 2 X 1
请问这道题咋做 :(x)X (x+1) X (x+2) X (x+3) =360
(x-1)^3(x+1)(x-2)/(x+4)
x(x+1)(x+2)(x+3)+1 (换元法)
计算 x(x+3)-(x-1)(x-2)
化简:x(2x+1)-x(x-3)
lim( x→∞)(1+x / x)^3x
(x+2)(x-2)+16 (x-1)(x-2)+3x(x+3)-4(x+2)(x-3)(x+2)(x-2)+16 (x-1)(x-2)+3x(x+3)-4(x+2)(x-3)
x+(x+1)/3
(x+1)(x+2)(x+3)(x+4)+1(x+1)(x-2)(x+3)(x-4)+25
计算(x*x+4x+5)/(x+2)-(x*x+6x+10)/(x+3)+1
1/x(x+3)+1/(x+3)(x+6)+---+1/(x+27)(x+30)
(x-1/x+1 - x+1/x-3 )除 2/x²+2x+1
3/x-1=4/x 6/x+1=x+5/x(x+1)
化简 (3x/x-1 -x/x+1)÷x/x²-1
【(Xˇ2-X)/x】 ·【 x/(X+1)】+【(3x+1)】
x(x平方-1)+2X平方(X+1)-3X(2X-5)帮个忙