int a=1,b=2,c=3,t;while (a
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/30 08:08:30
x)+QH5I5I5).IUHI*'_`gCP?|͚';Ytߪ}N{gV"PCPc5X)HծU0
vtU=mOv>۽Ŷ:/o~ھ"bd h~qAb hq
void fun(int a,int b) { int t; t=a;a=b;b=t; } main()void fun(int a,int b){ int t; t=a;a=b;b=t; } main() { int c[10]={1,2,3,4,5,6,7,8,9,0}.i; for(i=0;i
#include void fun(int a, int b) { int t; t=a; a=b; b=t;main() { int c[10]={1,2,3,4,5,6,7,8,9,0), i; for (i=0; i
#include void fun(int a,int b) {int t; t=a;a=b;b=t; } main() {int c[6]={1,2,3,4,5,6},i;for(i=0;i
#include stdio.h void fun(int a,int b) { int t; t=a,a=b,b=t; } main() { int c[10]={1,2,3,4,5,6,7#include stdio.hvoid fun(int a,int b){int t;t=a,a=b,b=t;}main(){int c[10]={1,2,3,4,5,6,7,8,9,0},i;for(i=0;i
int a=1,b=2,c=3,t;while (a
c语言这段程序看不懂int fun(int a,int b,int c){ int t; t=(a>b)?(b>c?b:(a>c?c:a)):((a>c)?a:((b>c)?c:b)); return t; }
以下程序运行时的输出结果第一行至第四行分别为void swap1(int c[ ]){ int t;t=c[0];c[0]=c[1];c[1]=t;}void swap2(int c0,int c1){ int t;t=c0;c0=c1;c1=t;}main( ){ int a[2]={3,5},b[2]={3,5};swap1(a); swap2(b[0],b[1]);printf(“%d
%d
%
#includemain(){int a=1,b=2,c=2,t;while(a
main() { int a=1,b=2,c=2,t; while(a
int a=1,b=2,c=2,t; while(a
下列数组定义错误的是 A.int x=5,a[x]; B.int aa[1]; C.int aa[2][3]; D.int a['a'];
#include int f1(int a,int b)15,9 { int c; c=b%2; return a+c; }int f2(int a,int b){ int c;a+=a;b+=b;c=f1(a+b=14,++b9);return c;}void main(){ int a=3,b=4;cout
请问一下“void main() {int t,a,b,c;a=1;b=2;c=2; while(a
求a,b,c值要过程 int a=1,b=2,c=2,t; while(a
#include int a=3,b=5; max (int a,int b) {int c; c=a>b?a:b; return (c); } void main() {int
#includestdio.h main() { int a=1,b=2,c=3,t; while(a
矩阵相加(C++)#include using namespace std; const int rows=3;const int cols=3;void matrixadd(int *,int *,int *,int,int);int main(){int a[rows][cols]={{1,3,5},{7,8,11},{13,15,17}};int b[rows][cols]={{9,8,7},{6,5,4},{3,2,1}};int c[rows][cols]={0
void swap1(int c0[],int c1[]) { int t; t=c0[0];c0[0]=c1[0];c1[0]=t; } void swap2(int *c0,int *c1) {void swap1(int c0[],int c1[]){ int t;t=c0[0];c0[0]=c1[0];c1[0]=t;}void swap2(int *c0,int *c1){int t;t=*c0;*c0=*c1;*c1=t;}void main(){int a[2]={3,5},b[