2x-3y+4z=11 3x+y-z=3 x+y=z三元一次方程的解,2x-3y+4z=11 3x+y-z=3 x+y=z三元一次方程的解,
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x+y/2=z+x/3=y+z/4 x+y+z=27
x+2y=3x+2z=4y+z 求x:y:z
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
2x+z=10 x+y-z=4 3x-y-z=0
x=y/z=z/3,x+y+z =12,求2x+3y+4z是多少,
2x+3y+z=0 3x+y-4z=11 x+y+z=-3
2x+3y+z=0 3x+y-4z=11 x+y+z=-3
2x+y+2z=4,3x-2y+z=11,x+y-2z=-2
2x+y+2z=4 3x-2y+z=11 x+y+2z=-2
x+2y+4z=17 2x+y+z=7 3x+y+2z=11
1.{x:y:z=3:4:5 2x+3y-5z=-142.{x-y-z=-1 3x+5y+7z=11 4x-y+2z=-13.{x+y=1 x+z=0 2x+y+2z=44.{x-y+z=-3 2x-y-z=-2 -3x+y+z=-15.{x-y+z=-3 3x+y-4z=6 2x+y-z=36.{x-2y+5z=16 2x+y-5z=7 2x-y+z=38
x-y-z=-1 3x+5y+7z=11 4x-y+2z=-1 分别求出x=?y=?z=?
三元一次方程 X-y-z=-1 3x+5y+7z=11 4x-y+2z=-1 X=?Y=?Z=?
(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=?
证明 :x/(y+z)+y/(z+x)+z/(x+y)>=3/2其中 x,y,z>0
x/2=y/3=z/5 x+3y-z/x-3y+z
若x+y+z=3y=2z,则x/x+y+z=?