(y+2)=1+2y,
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对于(y一撇)y`=y/x(y-1)求导,我求的结果是y``=-y^2-y`x+y/x^2(y-1)^2 怎么不对啊,我的求导过程是:y`x(y-1) - [x(y-1)]` y y`xy-y`x-(y-1+xy`)y -y^2-y`x+yy``=-------------------------=----------------------=-----------------x^2 (y-1
(1-Y)²=2Y(Y+1)
方程y''=(1+y'*y')/2y的通解
(y+2)=1+2y,
y'=1+y^2
y(y-2)²-y(y+3)(y-5) y=1/2 化简求值
y(y-2)²-y(y+3)(y-5) y=1/2 化简求值
y(y-2)²-y(y+3)(y-5) y=1/2 化简求值
方程5y(2y-3)=(y+2)(y-2)-1
常微分方程求解:(1)1+y'=e^y (2)xy'+y=y^2
(y-1)(y+2)=2y(1-y)(因式分解)
y‘=y-(2x/y),y(0)=1
(y+1)分之(2y+3)=(3y+4)分之(6y+7)
化简求值:(y-2)(y²-6y-9)-y(y²-2y-15)其中y=1/2
已知y=-2,求2y-2/y^2-2y+1+y+1/y-1-y的值
化简求值:【(x+Y)(X-Y)-(X-Y)的平方+2Y(2-Y)】除4Y,其中X=1 Y=2
(y-2)(y^2-6y-9)-y(y^2-2y-15),其中y=1/2.先化简再求值.
解方程:(y-3y+2)(y+3y-2)=y(y+3)(y-3)