X+Y=18,Y+Z=12,X+Z=8. 帮忙算下XYZ.
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解方程 x(x+y+z)=6 y(x+y+z)=12 z(x+y+z)=18
解方程组{x(x+y+z)=6,y(x+y+z)=12,z(x+y+z)=18
(x+y-z)(x-y+z)=
X+Y+Z=?
x/y=(x+z)/(y+z)y/z=(x+y)/(x+z)
已知 x/(y+z)+y/(z+x)+z/(x+y)=1求 (x*x)/(y+z)+(y*y)/(x+z)+(z*z)/(x+y)=?
(y+z)/x=(z+x)/y=(x+y)/z求x+y-z/x+y+z的值
x-4y+z=-302x+y-z=18x--y-z=7
x+y=8 y+z=12 x+z=10 x+y+z=
x+y=8 y+z=12 x+z=10 x+y+z=
X+Y+Z=26X-Y=12X-Y+Z=18
X+Y=18,Y+Z=12,X+Z=8. 帮忙算下XYZ.
fangchengzu:X+Z=Y 7Z=X+Y+Z X+Y+Z=14
z+=x>y?++x:
方程组 (1) x+2y-3z=12 x-3y+2z= - 13 x-y-z=0 (2) x+ y=z 5x-y+z=18 2x+5y+3z= -1
用行列式的性质证明:y+z z+x x+y x y z x+y y+z z+x =2 z x y z+x x+y y+z y z x 这个怎么证?
x=y; y=z; z=x/y
x+y+z=12 x-y+z=2 x-z+y+a=90 x+y+a+z=100,求x y z a