lim (x^2 +x)/x^4-x+1 x区域无限大 求极限
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/11 01:13:38
x)UШ3RЮԯ3ѭ6TxڳϦ/x9s%mlz6ȱI*'Y~
y6Af=ٌOv[lN3YrΧ6>_d'lNs@?dG/g.:l}.U0;Lk*胄t!\&X.xc#Wnz0
mM}
C]mk*
lim(x+1)^x+1(x+3)^x+3/x^2x+4 x趋于无穷
lim(1-x)^(2/x) x->0
lim(x)lim(x→∞) [(x-1)/(x+1)]^2x 为什么 lim(x->∞) {[(-2)/(x+1)]*2x} = -4
lim(x->2) {(3x+16)^1/2-4}/x
lim x→∞(2x+1)/(3x-4)
lim(x→0)(a^2x-1)/4x
关于极限1.lim((x^-1) + (x^-4))/((x^-2) - (x^-3)) x-> 正无穷2.lim ((e^x) - (e^-x))/((e^x) + (e^-x)) x-> 负无穷
求 lim(x→1)sin(x+1)/x+1 求 lim(x→2)x²-4/x-2
1、lim(x->无穷大) e^x arctanx2、lim(x->0)sinx√1+sin(1/x)3、lim(x->无穷大)【(√x^2+x+1)-【(√x^2-x+1)】4、lim(x->无穷大)((x+{x+(x)^0.5]^0.5}^0.5)/(2x+1)^0.55、lim(x->0)(sin3x+x^2sin1/x)/((1+cosx)x)6、lim(n->无穷大)(2^n)(si
lim x-1/x平方+3x-4 x-1
lim(x^2+1/x^2-2x)^x=?
Lim(x>1) x-1/x^2+x-2.计算
lim x→1 x-1/x^2-x
lim(x->无穷大){(2^x-3^x)/2}^(1/x)
Lim [x^2/(x^2-1)]^x (x→∞)
lim x->正无穷大 x ( sqrt(x^2+1)-x )
lim(x->0)((2-x)/(3-x))^1/x
lim(1+x/x)2x (x→∞)