化简2^2N+1-(4^2N+16^N)求大神帮助
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化简:1/(n+1)(n+2)+1/(n+2)(n+3)+1/(n+3)(n+4)
化简:2^4n+1-(4^2n+16^n)
化简:2^4n+1-(4^2n+16^n)
[3n(n+1)+n(n+1)(2n+1)]/6+n(n+2)化简
[3n(n+1)+n(n+1)(2n+1)]/6+n(n+2)化简
化简n分之n-1+n分之n-2+n分之n-3+.+n分之1
化简n分之n-1+n分之n-2+n分之n-3+.+n分之1
2^n/n*(n+1)
证明不等式:(1/n)^n+(2/n)^n+(3/n)^n+.+(n/n)^n
化简(n+1)(n+2)(n+3)
根号【(2n+1)/(n²+n)】平方-4/(n平方+n )化简
化简[n^2+(n+1)^2]/n(n+1) 化简额
lim(n+3)(4-n)/(n-1)(3-2n)
lim(n^3+n)/(n^4-3n^2+1)
化简16^n+2×4^n-1/8^2n×5^2n+4×2^n/5^2n+3×2^n+3
Sn=n(n+2)(n+4)的分项等于1/6[n(n+2)(n+4)(n+5)-(n-1)n(n+2)(n+4)]吗?
(n+2)!/(n+1)!
(n+1)(n+2)/1 +(n+2)(n+3)/1 +(n+3)(n+4)/1