log2(9^x-5)=log2(3^x-2)+2怎么解?用图像可以吗
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log2^(x^log2^x)=?
log2 (x + 3) + log2(x + 2) = 1log2 (x + 3) + log2(x + 2) = 1
[log2 1]+[log2 2]+[log2 3]+[log2 4]+[log2 5]+...+[log2 1024]=?[x]表示不超过x的最大整数2为底 答案是8204
log2(x – 2 ) + 2 = log2(5)log2(x – 2 ) + 2 = log2(5)
log2(x – 2 ) + 2 = log2(5)log2(x – 2 ) + 2 = log2(5)
解方程log2(9^x - 5)=log2(3^x - 2)的平方 详细!
解方程log2(9*x-5)=log2(3*x-1)+1,
解2log2^(9^x-5)=log2^(3^x-2)+2
log2(9^x-5)=log2(3^x-2)+2怎么解?用图像可以吗
解-log2^[9^(x-1)-5]=-log2^[3^(x-1)-2]-2
解-log2^[9^(x-1)-5]=-log2^[3^(x-1)]-2
解方程:log2(9^x - 5)=log2(3^x - 2)+2解方程log2(9^x - 5)=log2(3^x - 2)+2希望有详细过程.注:log2中的2为log的下标
log4(log2^x)=log2(log4^x)求log2^x
log2(-x)=x+
解2log2^(x-5)=log2^(x-1)+1
求解log2(3x)=log2(2x+1)
log2(x+1)+log2(x+8)=3的解集是?
|[log2(x)]^2-3log2(x)+1|