(1)[(2y+1)(2y-1)]^2 (2)(x+y)(x^2+y^2)(x-y)(x^4+y^4) (3)(2x+y+z)(y-2x-z)
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/04 23:42:14
xSAJ0JAĠ;H@npn\^u3Rfp&KU9S`
aK1Y-,,*+2J]KdzdkZIgu||:H=0cb @W ,SAC/F\c2}3>+ 煕tBszup#9Nr8Xғ|]龽}8Um(Y"_ b<4+ĽMktFϸ~]7̀
y (3y^2+8y-3)-6y(3y+2y-1)+9y
(y平方+2y)(y平方+2y+2)+1
方程y''=(1+y'*y')/2y的通解
y'=1+y^2
-1+y+20y^2
通分 y+3/y*y-6y+9,1/2y+6,y-1/y*y-9
[(-x-y)(-x+y)-(x+y)^2-x(y-y^2)}÷1/2y
y(y-2)²-y(y+3)(y-5) y=1/2 化简求值
y(y-2)²-y(y+3)(y-5) y=1/2 化简求值
y(y-2)²-y(y+3)(y-5) y=1/2 化简求值
已知y=-2,求2y-2/y^2-2y+1+y+1/y-1-y的值
(y-2)(y^2-6y-9)-y(y^2-2y-15),其中y=1/2.先化简再求值.
方程y''-4y'+13y=0的通解方程y''=(1+y'*y')/2y的通解
4y²-4y/y²-2y+1÷(y+1/y-1-y-1/y+1)÷(3y+3)
[(-2x-y)^2-(2x+y)(2x-y)]÷2y-1/2y
解方程:3y^2-(2y+1)(y-1)=(y-5)(y+1)
解方程3y^2-(2y+1)(y-2)=(y-5)(y-1)
5y∧2-(y-2)(3y+1)-2(y+1)(y-5)