求解:2log5 25-3log2 64哪位好心的朋友帮帮忙?给我一个详细点的过程,小妹感激不尽
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2log5(底)25-3log2(底)64求解 log2(底)(log2(底)32-log2(底)3/4+log2(底)6
lg(1/4)-lg2(5) 2log5(10)+log5(0.25) 2log2(25)-3log2(64) log2(log2(16) )
2log5(25)-3log2(64) 如题`怎么做?
2log5^25–3log2^64等于?
2log5(25)+3log2(64)-8ln1等于多少
2log5 25+3log2 64等于多少
2log5(底数) 25+3log2(底数) 64-8log2 (底数)1的值为是多少,
2log5 10+log5 0.25= 2log5 25-3log2 64= log2(log2 16)= 已知lg2=a,lg3=b,求log3 4,log2 12
求解:2log5 25-3log2 64哪位好心的朋友帮帮忙?给我一个详细点的过程,小妹感激不尽
2^(1/2log2 3)+(1/25)^log5 3=
log3 25×log2 27×log5 2^-3=_____
2log5(25)-3log2(64)=?注意:5和2对数的底数
2log5(底数) 25+3log2(底数) 64-8log7 (底数)1的值为是多少,
2log5(25)+3log2(64)请使用换底公式解决
(log3^4+log5^2)(log2^9+log2^根号3)
(log5(10))^3-(log5(2))^3-3log5(10)*log2(5)
1.lg1/4-lg25=?2.2log5(底数)10+log5(底数)0.25=?3.2log5(底数)25-3log2(底数)64=?4.log2(底数)(log2(底)16)=?
log的计算 :log2(20)-log4(25)= log3(2)×log2(5)×log5(3)=?log2[log2(32)-log2(3÷4)+log2log的计算 :log2(20)-log4(25)= log3(2)×log2(5)×log5(3)=?log2【log2(32)-log2(3÷4)+log2(6)】=?lgx+lg(x+15)=2 ..X