2×4/1+4×6/1+6×8/1+.+2006×2008/1怎么计算?过程和结果都要!- 对不起 题目写错了.........应该是这样1/2×4+1/4×6+1/6×8+......+1/2006×2008
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|1/4-1/2|+|1/6-1/4|+|1/8-1/6|+```+|1/2008-1/2006|
1/2+1/4+1/6+1/8+.1/n
1+6+6+8+4+2+6+6+5+4+4+1+4+7+45
1+1/2+4+1/2+4+6+1/2+4+6+8+.+1/2+4+6+8...+20
1/2*4+1/4*6+1/6*8+1/8*10+---+1/198*200
10,1,8,1,6,2,4,6,2,().
1/2*4*6+1/4*6*8+1/6*8*10+.+96*98*100
1/2*4+1/4*6+1/6*8+.+1/2006*2008=(1/2*4)+(1/4*6)+(1/6*8)+..........+(1/2006*2008)
1/2*4+1/4*6+1/6*8+1/8*10.1/2006*2008
计算1/2*4+1/4*6+1/6*8+.+1/2002*2004+1/2004*2006
1+1+2+1+2+6+4+5+8等于
1/4+5/8+6/2=?
1,2,3,4,5,6,8
1×2×3×4×5×6×8
2/1+4/1+4/1+6/1+8/1+16/1+32/1=?
1,2,4,6,
[2^4+1/4)(4^4+1/4)(6^4+1/4)(8^4+1/4)(10^4+1/4)】/[1^4+1/4)(3^4+1/4)(5^4+1/4)(7^4+1/4)(9^4+1/4)]
2+2+5+0+4+1+6+8+2+6