log2 (2^x-1)·log2 [2^(x+1)-2]

|[log2(x)]^2-3log2(x)+1| log2 (2^x-1)·log2 [2^(x+1)-2] log2 (2^x-1)·log2 [2^(x+1)-2] log2(2X-1) log2 (x + 3) + log2(x + 2) = 1log2 (x + 3) + log2(x + 2) = 1 [log2 1]+[log2 2]+[log2 3]+[log2 4]+[log2 5]+...+[log2 1024]=?[x]表示不超过x的最大整数2为底 答案是8204 log2(x-1)>2定义域log2(x-1)>2 定义域 解方程log2(2-x)=log2(x-1)+1 解2log2^(x-5)=log2^(x-1)+1 求解log2(3x)=log2(2x+1) 不等式log2(2x+3)>log2(x+1)的解集是 解不等式log2(4x+8)>log2(2x+1) 化简：(log2(x/4))*(log2(x/2)) 不等式log2(2^x-1)·log2(2^(x+1)-2不等式log2(2^x次幂-1)·log2(2^x+1次幂-2) 不等式log2(x^2-1) |2x-log2^x| 【x】表示不超过实数x的最大整数,则【log2 1]+[log2 2]+[log2 3]+.+[log2 2012]等于? 求值域,log2 x/2·log2 x/4（x∈[1,8]）