1.化简:6√x/3-3/4√4x/3+x√12/x2.若等腰三角形两边长分别为m,n,且2√3m-6+3√2-m=n-6,求这个三角形的周长和面积.
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难倒爱因斯坦的九宫格X 7 X | X 8 1 | X X X |X X X | X 4 X | 7 5 9 |X X 5 | 7 X 9 | X 1 4 |5 X X | X X 8 | 3 9 X |3 9 6 | 4 X 7 | X X 2 |X 8 7 | 9 X X | X X X |4 X X | 6 X 5 | X X X | X X 4 | X X 1 |2 X X | X X X | X X X | X 3 X | X X X |X 6
化简:[√(x^2-6x+9)/x^2-x-12]*(x^3-16x)/(x^2-3x)-1/(x+3) {x>3}
3x·x-5x-122x·x·x-x·x-4x+3x·x·x-6x-5x·x+6x+64x·x+12x+7