X^2+Y^2=1 ,a^2+b^2=3 ,ax+by的最小值为?X^2+Y^2=1 ,a^2+b^2=3 ,ax+by的最小值为?

集合A={(x,y)|x-2y=1}B={(x,y)|x+3y=6},则A∩B= A∪B=? A={(x,y)|y=-x^2+mx-1},B={(x,y)|y=3-x,0A={(x,y)|y=-x^2+mx-1},B={(x,y)|y=3-x,0 集合A={（x,y)|y=-x^2+mx-1},B={(x,y)|y=3-x,0 集合A={y/y=1-x-4/x},B={X/X^2-(3+a)X+3a 集合A={y|y=1-x-(4/x)},B={x|x^2-(3+a)x+3a 1、(-y^3)^5/y^3/ y^2+2(-y)^102、(x-y)^7/(y-x)^6+(x+y)^3/(x+y)^23、已知X^a=5,x^b=3,求X^(3a-2b)的值 已知：A=X*X-3xy+y*y,B=2x*x+xy-3y*3y.求A+B,A-B,A+2B 【高一数学】已知集合A={(x,y)|y=2x+1},B={(x,y)|y=x+3},a∈A,且a∈B,则a为__已知集合A={(x,y)|y=2x+1},B={(x,y)|y=x+3},a∈A,且a∈B,则a为__ A={(X,Y)|X+Y>=1},B={(X,y)|X^2+y^2=1},B={(X,y)|X^2+y^2 初一因式分解练习题,谁好心帮我解下表示平方1.2X~-3XY-X2.(X+Y)~(X+Y)(X-Y)(X+Y)(Y+Z)3.3X(a+2b)~-6XY(a+2b)4.a(x-y)-b(X-Y)-C(Y-X)5.(b-a)~-2a+2b6.(x-y)~-m(y-x)+y-x7.x(x-y)(a-b)-y(y-x)(b-a)8.已知a+b=13,ab=40,求 b+ab~的值 填空：(b-a)(2x-y+1)=(a-b)( ) 设集合A=｛y/y=x²-2x+3,x∈R｝,B=｛y/y=-x²+2x+10,x∈R｝,求A∩B设集合A=｛（x,y)/y=x+1,x∈R｝,B=｛（x,y)/y=-x²+2x+3/4,x∈R｝,求A∩B x+y-(2x-y)(x+y)=?12(a^2-b^2)^2-3(a^2+b^2)(a+b)^2等于多少(2a-b)(2a+3b)+3a(b-2a)=-(2a-b)( ),a(x-3)(5-x)+b(3-x)(x-5)=( )(x-3)(a+b)代数式15x^3y^3(x-y),6x^2y^2(y-x),-120x^3y^3（x-y）（x+y）的公因式是?a-b+k(b-a)=( )(k-1)a(b-c)+c-b=(b-c) 集合A={y|y=x²-4x+3},B={y|y=-x²-2x},那么A∩B=1、集合A={y|y=x²-4x+3},B={y|y=-x²-2x},那么A∩B=2、集合A={y|y=x²-4x+7},B={y|y=-x²-4x+3},那么A∩B= 集合A={y|y=x²-4x+3},B={y|y=-x²-2x},那么A∩B=1、集合A={y|y=x²-4x+3},B={y|y=-x²-2x},那么A∩B=2、集合A={y|y=x²-4x+7},B={y|y=-x²-4x+3},那么A∩B= 设A={(x,y)}|3x+2y|.设A={(x,y)}|3x+2y|.B={(x,y)|x-y=2|},C={(x,y)|2x-2y|=3},D={(x,y)|6x+4y=2|},求A∩B,B∩C,A∩D设A={(x,y)|3x+2y=1}.B={(x,y)|x-y=2},C={(x,y)|2x-2y=3},D={(x,y)|6x+4y=2},求A∩B，B∩C，A∩D 1（x-3x-1）（x+3y-1)2（3x-2y+1/4）²3（a+b)²-（a-b）²4 [2x²-（x+y)(x-y)][（-x-y)×（y-x)+2y²],其中x=1 y=25[（0.5x-y)²+（0.5x+y)²]（0.5x²-2y²）6（a+3b)²-2（a+3b)(a-3b)+(a-3b)²7 a={(x,y)/2x+y=4}b={(x,y)/3x-2y=-1}A与B的交集为什么是{1,2}