复数z=(1-i)^10*(3-4i)^2/(-√3+i)^8的模为

若复数z=3-4i/1+i, 则复数共轭区间,z=? 复数z=(1+i)^2/(3-4i)则复数z的模为 已知复数z=（2+i)(i-3)+4-2i 求复数z的共轭复数~z及(~z) 若复数z满足(1-3i)z=10i,则z等于 若复数z满足(1—3i)z=10i.则z等于多少 已知复数z满足(1+2i)z=4+3i,求z F(z)=|1+z|-z的共扼复数,且F(-z)=10-3i,求复数z 已知复数z满足z*z拔=4,且｜z+1+√3i｜=4,求复数z 已知复数Z满足:|Z|=1+3i-Z,求[(1+i)^3*(3+4i)]/Z 已知复数Z满足:|Z|=1+3i-Z,求[(1+i)^2(3+4i)^2]/2Z 已知复数|z|=1+3i-z,求z? 已知复数z满足z*z-3i*z=1+3i,求z 已知复数z满足z=1+i+i^2+i^3+…+i^2015,则复数z=? 已知复数Z满足：|Z|=1+3i-Z,求复数Z 已知复数z满足I z+1+i I=I z-1+3i I,则IzI的最小值 复数z=[(1+i)^2+3(1-i)]/(2+i),若z^2+a/z 复数z=[(1+i)^2+3(1-i)]/(2+i),若z^2+a/z 复数z=[(1+i)^2+3(1-i)]/(2+i),若z^2+a/z